15p^2+5p=20

Solution for 15p^2+5p=20 equation:

15p^2+5p=20

We move all terms to the left:

15p^2+5p-(20)=0

a = 15; b = 5; c = -20;
Δ = b2-4ac
Δ = 52-4·15·(-20)
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-35}{2*15}=\frac{-40}{30}
=-1+1/3
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+35}{2*15}=\frac{30}{30}
=1
$